[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

Search:


View post   

>> No.12473293 [View]
File: 1.05 MB, 1215x1761, 503a708ab265359742bc2a2893fc23d599b1665a5ce588c4880999008e0cd98a.jpg [View same] [iqdb] [saucenao] [google]
12473293

>>12473113
We define [math]\chi _n : \mathbb{R} \rightarrow \mathbb{R}[/math] by [math]\max(n - n^4x, 0)[/math] if [math]x \geq 0[/math] and [math]\max(n + n^4 x, 0)[/math] if [math]x < 0[/math]. Unless I've done something wrong:
>[math]\chi _n[/math] is continuous
>[math]\int _{- \infty}^{\infty} \chi _n (x) \ dx = \frac{1}{n^2}[/math].
>[math]\chi _n[/math] has support in [math][-0.5, 0.5][/math] for [math]n \geq 2[/math]
Then, by setting [math]f(x) = \sum _{i = 2}^{\infty} \chi _n (x - n)[/math], we compute that [math]\int _{- \infty}^{\infty} f(x) \ dx = \sum _{n=2}^{\infty} \frac{1}{n^2}[/math], which is finite. Plus, since the components all have disjoint supports, we get to keep continuity.
Then you fuck around with some computations and conclude that [math]G(x)[/math] can't be Lipschitz because [math]f[/math] gets too fucking high (left to reader).
IIRC for continuous functions that's equivalent to boundedness of [math]f[/math].

>> No.11595667 [View]
File: 1.05 MB, 1215x1761, __remilia_scarlet_and_kuromi_touhou_and_1_more_drawn_by_satoupote__298547573128226eee5a32d4d9ef7d72.jpg [View same] [iqdb] [saucenao] [google]
11595667

>>11595648
>hey lad whachu doing
>ah, I'm just trying to put out this fire by throwing gasoline at it

Navigation
View posts[+24][+48][+96]