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>> No.11424069 [View]
File: 196 KB, 685x554, 1577652895674.png [View same] [iqdb] [saucenao] [google]
11424069

me too

>> No.11358129 [View]
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11358129

>>11356637
>300% efficiency (for every KW of electricity, you get 3 KW of heat)
Tou are confusing efficiency with coefficient of performance (CoP), which for a heat pump would be the ratio of the rate of heat *transfered* to whatever you are trying to warm up, to the power required. CoP can very easily be greater than 100%=1. Your typical heat pump can pull a performance of CoP=3.5
Basically, you are stupid.

>> No.11351761 [DELETED]  [View]
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11351761

>>11349953
>this system requires no electricity
If you are evaporating water into air in a tower, by the time the air reaches the spout, it will be quite cold. To condense the water and reclaim pure H2O, you need to decrease its entropy. To do this, you need to draw heat out of it. The only way to cool something that is already quite cool, you need something colder. This means refrigeration, which definitely needs a lot of power.
Unless you mean that the "super high speed" air is coming from the top of the spout, in which case your idea makes less sense.
The science of the hotness and wetness of air and how it draws in moisture is called "psychrometrics," by the way. Research that to learn more.

>> No.11287070 [View]
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11287070

>>11287010
>What I do is iterate over the portions, average the temperature of the neighbouring ones, subtract the temperature of the current portion, multiply by a constant, and add this to the temperature.
That doesn't sound right...The rate of change of the temperature of a single element is going to be proportional to the SECOND derivative of temperature over space. Basically the situation is this:
[eqn]\frac{\partial T}{\partial t}=\alpha\frac{\partial^2T}{\partial x^2}\implies \frac{\Delta T}{t}=\alpha\frac{\Delta(\Delta T)}{x^2} [/eqn]
The equation on the left is the heat equation for a thin rod, and alpha is the thermal diffusivity of the material. On the right, t is the time increment, and x is the size of each element. Basically, you get that the change in temperate of an element over a time increment is proportional to the *slope of the temperature gradient*, not the temperature gradient itself, all divided by x. Basically you need to find the dT/dx at each element, which is what you were already doing, but then you need to find how that value, the dT/dx changes over space.

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