/sci/ - Science & Math

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Sup /sci/
I've been running through math homework today and I am really stuck on this problem, please halp.

Gasoline is pumped into a cylindrical tank, standing verticall at a decreasing rate given at time t minutes by:

r(t) = 120 - 6t ft^3/min for 0 <=t <= 10

The tank has a radius of 5 ft and is empty at t = 0. What is the depth of the water in the tank at t = 4?

I know that it has to do integrals and related rates but I am not really sure how to apply the related rates, with the rate having minutes and the depth only being one dimension of feet but I am very lost.

Sup /sci/
I've been running through math homework today and I am really stuck on this problem, please halp.

Gasoline is pumped into a cylindrical tank, standing verticall at a decreasing rate given at time t minutes by:

<div class="math"> r(t) = 120 - 6t ft^3/min for 0 <=t <= 10

The tank has a radius of 5 ft and is empty at t = 0.
What is the depth of the water in the tank at t = 4?

I know that it has to do integrals and related rates but I am not really sure how to apply the related rates, with the rate having minutes and the depth only being one dimension of feet. I am very lost.</div>