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>> No.15264915 [View]
File: 610 KB, 900x748, __matara_okina_touhou_drawn_by_re_ghotion__9d28e93263e0576aeecf6eff9075baf0.png [View same] [iqdb] [saucenao] [google]
15264915

>>15263805
>Would you say it's sufficient to point out that the momentum operator is the derivative on polynomials, which I know to be linear.
Isn't that circular?
I mean the entire """definition""" you've given is just [math]P = \dfrac{d}{dx}[/math]. Unless I'm misunderstanding something?
>>15264636
For [math]x \in \mathbb{Z}_{17}[/math], [math]x^{17} = x[/math] (Fermat's little theorem), hence [math]x^{16} = 1[/math] (divide both sides), hence [math]x^{15} = x^{-1}[/math]
So the only solution is [math]x = 1[/math]

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