/sci/ - Science & Math

>>12733217
You're adding in an extra x. Given the ansatz [math] \theta (t) = Ae^{xt} [/math], you get the following equation: [eqn] x^2 Ae^{xt} + \frac{g}{L}Ae^{xt} = 0 \implies x^2 + \frac{g}{L} = 0[/eqn]