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>> No.15972893 [View]
File: 224 KB, 636x419, Hubbard open sets.png [View same] [iqdb] [saucenao] [google]
15972893

Can someone elaborate one this? I'm not quite understanding. If for a closed set, x + h is outside the domain, why not just use x - h instead? And if that's truly a problem, why not just take the derivative on the open set without the last bit that makes it closed? Or is this really only a problem with sets that are neither open nor closed?

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