/sci/ - Science & Math

[math]x^m\in x^mN=(xN)^m[/math], and since [math]xN\in G/N[/math], [math]|xN|[/math] divides [math]m[/math]. So, [math](xN)^m=N[/math], and [math]x^m\in N[/math].

There we go, that was simpler than I thought. Thanks again.

>>7307010
those aren't modern feathers

>>7041369
shit, appchanx keeps auto posting

>PS. To anyone who has EVER donated to these charities, thank you for my life and for my (now 5yr old) daughter.
shit, right in the feels

Alright, this is probably a little simple for /sci/, but it's been bugging me.

I'm trying to prove that d/dx g(x)/h(x) is the same as d/dx g(x)*h(x)^-1

All the proofs of the first example turn it into a product anyway, g(x) = f(x)*h(x), but I'm sure the second example should play out the same. I get it almost all the way to the end and the only thing I'm missing is the h'(x) in the numerator.