/sci/ - Science & Math

>>10374091
lol wtf. just do
[math] x^n-1 = (x-1)(x^{n-1}+x^{n-2}+\dots + x+1) \implies \frac{x^n-1}{x-1} = \sum\limits_{j=0}^{n-1}x^j [/math]
Take the limit as [math]n\to\infty [/math] of both sides to get that
[math] \frac{1}{1-x} = \sum\limits_{j=0}^{\infty}x^j [/math] when 0<x<1

>>9020474
>/sci/ is a calm /pol/ sub-board

>physics major w/ high IQ

>>7079742
those people cannot Brie serious