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>> No.11538167 [View]
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11538167

>>11537122
Typo: [math](m+1 \quad k-m)[/math]
>>11537448
>I have no idea what you're trying to do
I'm decomposing the permutation as a product of transpositions and counting the transpositions to obtain the parity.
>His original answer is correct.
His original answer coincides with my formula, anon. [math](-1)^{ \lfloor (4n+m)/2 \rfloor} =(-1)^{ \lfloor 2n + m/2 \rfloor } = (-1)^{2n + \lfloor m/2 \rfloor } = (-1)^{ \lfloor m/2 \rfloor }[/math], which lets you see the four period explicitly.
>>11537860
Yeah, I made a typo with [math]\mathbb{Z}^2[/math]
>>11537932
>Yeah, no, he understands perfectly well what level of complexity you're at.
To be entirely honest, I had no idea what the fuck anon was asking until he mentioned linear algebra a couple posts later, and even then half of my post was literally guessing what he meant.

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