/sci/ - Science & Math

If you have a function f(x) and you start with some starting value, say x=1 and then feed the output of the function back to itself and repeat, in which cases is it possible to have a simple formula for the value of the n:th iteration?

As an example, if f(x)=2x and you start with x=1, the n:th iteration will be 2^n, resulting as a nice formula. But what if the function is much more complicated? I'm wondering for which type of functions this type of thing is possible to do and which not. It's interesting because I've never seen this type of maths in school and it feels weird to think about.

>>15277064
But isn't µ determined by the angle though? Because obviously the angle matters also. You could theoretically have the the block at just the right angle so that the force is zero, or something like 45 degrees which would make it well greater than zero, or anything between.