/sci/ - Science & Math

>>11620429
You know that this equality is over [math]\mathbb{F}_2[x][/math], not polynomials over R, right?
It's simple computation, if w^4 + w + 1 = 0, then
w^8 + w^2 + 1 = (-w-1)^2 + w^2 + 1 = 2w^2 + 2w + 2 = 0.