/sci/ - Science & Math

>>15397592
my original original idea from years back was to fudge the function like so: a Taylor series is always exactly equal to the function, at the center of convergence (because the first term of a Taylor series is always just [math]f(a)[/math]). So, if we just scoot the Taylor series over from [math]-\infty[/math] to [math]\infty[/math], plotting the value at the center of convergence [math]f(a) \forall a[/math], we would have the function.
See here:
https://www.desmos.com/calculator/tu3vppf2om
but that's when I realized we would need to know the function, to find the function, and we're stuck