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>> No.11642447 [DELETED]  [View]
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11642447

>>11641213
If and only if [math]Ax=-Bx[/math] implies that [math]Ax=0[/math], if and only if [math]ker ~ A+B = ker ~ A \cap ker ~ B[/math].
>>11641883
Wolfram confirms that your computation is correct.
I think the issue is literally just that you gave the first order term rather than the first order polynomial.
So it possibly should be [math]P_1(x) = 3x+1[/math]
>>11642388
As is? No.
Set [math]A_1[/math] as literally any non-invertible matrix and [math]A_0[/math] as minus the identity.
You trivially get [math]A_1X = I[/math], which has no solution.
He could be talking about the matrix form for complex numbers.
https://en.wikipedia.org/wiki/Complex_number#Matrix_representation_of_complex_numbers

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