/sci/ - Science & Math

>>16003127
A4 and A5 have a 1 and 2 by 8
A3 and B3 have a 3 and 1 by 4. since A already has its 1, A3 is 3 and B3 is 1. You knew this much.

B5 and B6 are either 1 and 5 or 2 and 4 by 9. But you know B's 1 is taken, so it's 2 and 4. This also means that you know B1, B2, and B4 must be 3, 5, and 6.
5 tells you that B4 and C4 have 1 and 5 or 2 and 4. But we know B4 has to be one of 3, 5, or 6, so B4 must be 5 and C4 must be 1. So A5 is 1 and A4 is 2.
Furthermore, 3 tells you that B2 and C2 are 1/6, 2/5, or 3/4. From this list, B2 must be 3 or 6. But B2 being 6 would mean that C2 is 1, and C's 1 has already been used, so B2 is 3 and C2 is 4. B1 is 6, then.
10 says that C5 and C6 are 4/5 or 3/6, but they can't be the former, so they're the latter. This suggests that C3 and C1 are 2 and 5.
2 says that C1, D1, and E1 are some combination of 1, 2, and 3. Combining this with the previous, we know that C1 must be 2, so C3 is 5.
6 says that D5 and E5 have a 5 and 6, so that rules out C5 as 6. Thus C5 is 3 and C6 is 6. Because B1 and C6 are 6, that rules out A1 and A6, so A2 is 6 instead.
7 says that D6 and E6 are 3/5 or 2/6, but C6 is 6, so they have to be 3/5. That means that A6 can't be 5, so it must be 4 and A1 must be 5. Then B5 is 4 and B6 is 2.

We haven't even touched half of the squares yet.
By 11, D2 and D3 are 1/5 or 2/4. But 3 has both 1 and 5, so it has to be the latter, and C2 is already 4, so D2 is 2 and D3 is 4.
Also, since we know that D6/E6 is 3/5, F6 must be 1.
This forces D's 1 to be D1, and E's 1 to be E2, which in turn forces F2 to be 5.
2 also tells us that E1 is 3, so F1 is 4.
This forces E4 to be 4.
Since D5 and E5 are 5/6, F5 is 2, and that's sufficient to force the rest of the square.