/sci/ - Science & Math

>>12203182
Expand it and you will get [math]I - A + A^2 - \cdots + (-1)^k A^k = 0 \Leftrightarrow I = A - A^2 + \cdots -(-1)^k A^k = A(I - A + A^2 - \cdots -(-1)^k A^{k-1})[/math]. The stuff inside the parentheses is now the inverse of [math]A[/math]. Warning: I may have made a mistake with the signs, but the idea is the same, nevertheless.

>>11811736
Live up to your promise or die trying!