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>> No.11603794 [DELETED]  [View]
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11603794

>>11603725
What definition?
[eqn] \mathcal{F}^{-1}\{\text{unit rectangular function centered at origin}\}=\int_{-.5}^.5\exp{j\omega t}\text{ d}\omega= [/eqn]. Because the Laplace transform of the unit impulse is unity, the transfer function of any LTI system is going to be the LT of the output itself. Therefore [math]\ unit\ impulse\ [/math] is just the inverse LT (FT) of the transfer function. It makes intuitive sense why the rectangular function is the desired transfer function in this case.

>> No.11402476 [View]
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11402476

>>11397786
>there is no voltage drop/voltage drop is completely insignificant
>so what happens if I place both terminals of a capacitor at the same voltage
The answer is fucking nothing.
>>11402427
Got his ass.

>> No.11397590 [DELETED]  [View]
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11397590

>>11397210
I will be more quantitative than that other guy. The physical principle at play is Fourier's law, which states that the heat flux conducted through a material is proportional to the temperature gradient over that material. The human body dissipates heat at a rate of something like ~200 Watts/square meter. If you cover your whole body with a blanket, you are putting thermal resistance between yourself and your surroundings. Say you have a blanket that has a thermal conductivity of 0.05 W/m*K (typical) and a thickness of 1 centimeter. Say you want to find the lowest temperature you could exist in such that you can maintain a (surface) body temp of 37 degrees C. Then, 37-T=(200*0.01)/0.05 so T = -3 degrees C or a little below freezing. The is an extremely simplified model that does not consider the still air trapped between your body in the blanket, or any notion of wind or convection. These would tend increase and decrease the possible temperature differential, respectively.
>>11397319
yw <3
>mrs. brisby poster
also me
>>11397425
>without a connection to ground
Sorry, I misunderstood. Ideally, if you are not grounded and grab one hot wire with one hand, you hand is more or less just going to be at a constant voltage. This assumption falls apart at very high voltages because real wires have finite conductivity, and there will be a voltage drop over your hand. Current then flows through your hand per Ohm's law. There's a reason why HV workers wear Faraday suits.
>>11397440
Does it? It reminds me more of root-mean-square.

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