/sci/ - Science & Math

>>11544516
>these other answers
It's very simple: the rate at which the area under a curve changes is proportional to the height of the curve itself.

>>11408949
>in capacitors is the charge stored in the dielectric between the plates
No. It is stored on the plates.
>Does one side produce the stored charge and the other dissipate it?
Both plates store charge of opposite sign.
>And is the energy going in the same as that coming out when shorted?
Dont know what this means
>Inductors store a magnetic charge but only release it when the circuit is open, what's going on here?
Ampere's law and Faraday's law. Any current in a loop induces a magnetic field through the center, but only a changing magnetic field induces a current in the loop that surrounds the field. The direction of the field and induced current are related by Lenz's law.
>>11409821
tl;dr

>>11364180
I ask because the problem is really easy if it is hung. You know the original length of the rod [math] L_0 [/math]. You know the tension on the rod [math] P [/math]. You know the shape and of the rod [math] R [/math]. You know the density of the rod [math] \rho [/math]. It's simple then that the average stress in the middle rod is [eqn]
\sigma=\frac{P+\pi R^2L_0\rho}{\pi R^2} [/eqn] You are given Young's modulus [math] E [/math]. The strain at the middle is thus [math]\epsilon=\sigma/E=\delta/(L_0/2) [/math]. So the displacement at the middle is
[eqn] \delta=\epsilon L_0/2=\frac{PL_0+\pi R^2L_0^2\rho}{2E\pi R^2} [/eqn].
It's the exact same process for the whole rod. If you need a formula to remember, remember [math] \delta=\Delta L=PL_0/EA [/math].