/sci/ - Science & Math

The moving air replaces the air heated by your body heat in the immediate vicinity of your skin with cooler air.

<span class="math">(P \to Q)[/spoiler]

This is only false when ''P'' is true and ''Q'' is false. Therefore, we can reduce this proposition to the statement "False when ''P'' and not-''Q''" (i.e. "True when it is not the case that ''P'' and not-''Q''"):

<span class="math">\neg(P \wedge \neg Q)[/spoiler]

The elements of a logical conjunction can be reversed with no effect:

<span class="math">\neg(\neg Q \wedge P)[/spoiler]

We define <span class="math">R[/spoiler] as equal to "<span class="math">\neg Q[/spoiler]", and <span class="math">S[/spoiler] as equal to<span class="math">\neg P[/spoiler] (from this, <span class="math">\neg S[/spoiler] is equal to <span class="math">\neg\neg P[/spoiler], which is equal to just <span class="math">P[/spoiler]):

<span class="math">\neg(R \wedge \neg S)[/spoiler]

This reads "It is not the case that (''R'' is true and ''S'' is false)", which is the definition of a material conditional. We can then make this substitution:

<span class="math">(R \to S)[/spoiler]

When we swap our definitions of ''R'' and ''S'', we arrive at the following:

<span class="math">(\neg Q \to \neg P)[/spoiler]

<span class="math">(P \to Q)[/spoiler]

This is only false when ''P'' is true and ''Q'' is false. Therefore, we can reduce this proposition to the statement "False when ''P'' and not-''Q''" (i.e. "True when it is not the case that ''P'' and not-''Q''"):

<span class="math">\neg(P \and \neg Q)[/spoiler]

The elements of a logical conjunction can be reversed with no effect:

<span class="math">\neg(\neg Q \and P)[/spoiler]

We define <span class="math">R[/spoiler] as equal to "<span class="math">\neg Q[/spoiler]>", and <span class="math">S[/spoiler] as equal to<span class="math">\neg P[/spoiler] (from this, <span class="math">\neg S[/spoiler] is equal to <span class="math">\neg\neg P[/spoiler], which is equal to just <span class="math">P[/spoiler]):

<span class="math">\neg(R \and \neg S)[/spoiler]

This reads "It is not the case that (''R'' is true and ''S'' is false)", which is the definition of a material conditional. We can then make this substitution:

<span class="math">(R \to S)[/spoiler]

When we swap our definitions of ''R'' and ''S'', we arrive at the following:

<span class="math">(\neg Q \to \neg P)[/spoiler]

We are going to prove that 1=0. Start with the addition of an infinite succession of zeros
<span class="math">0 = 0 + 0 + 0 + \cdots[/spoiler]
Then recognize that <span class="math">0 = 1 - 1[/spoiler]
<span class="math">0 = (1 - 1) + (1 - 1) + (1 - 1) + \cdots[/spoiler]
Applying the associative law of addition results in
<span class="math">0 = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + \cdots[/spoiler]
Of course <span class="math">-1 + 1 = 0[/spoiler]
<span class="math">0 = 1 + 0 + 0 + 0 + \cdots[/spoiler]
And the addition of an infinite string of zeros can be discarded leaving
<span class="math">0 = 1 \,[/spoiler]

<span class="math">Q.E.D.[/spoiler]

>>1825908

This. This. This.

Fucking this.

>My face when people save pictures of gay porn onto their computer to insult engineers
>My face when they think engineers are the gay ones
Oh /sci/borgs, u so crazy

>>1494554
>accretion dicks

>>1492070

Obviously? The core.

Black holes don't exist, they're supermassive dark stars with an escape velocity greater than the speed of light hence they can't be directly detected. Sounds quite rational to me. Why assume they're some wololol voodoo-shit that break the laws of physics?

>>1474600

http://www.remnantofgod.org/creation.htm

>The Messages given to Rael by our human creators from space