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>> No.4421765 [View]
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4421765

>>4421737
R_1, R_3 and R_4 are in line.

In line = same current.

R_2 is parallel to the line with R_1, R_3 and R_4

R_ab = R_2 || (R_1 + R_3 + R_4)
R_ab = 2 Ohm || (1 Ohm + 3 Ohm + 4 Ohm)
R_ab = 2 Ohm || 8 Ohm
R_ab = 2 Ohm * 8 Ohm / ( 2 Ohm + 8 Ohm )
R_ab = 16 Ohm² / 10 Ohm = 1,6 Ohm

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