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/sci/ - Science & Math

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>> No.11884652 [View]
File: 220 KB, 1600x1200, __natsuiro_matsuri_hololive_drawn_by_dark_talker__1fe67a4e3cb4c98e33121ffb0f1e5130.jpg [View same] [iqdb] [saucenao] [google]
11884652

>>11884628
Sure.
[math]A \cap (B \Delta C) = A \cap (B - C \cup C - B) = [A \cap (B-C)] \cup [A \cap (C-B)] = [(A \cap B) - C] \cup [(A \cap C) - B] = [(A \cap B) - (A \cap C)] \cup [(A \cap C) - (A \cap B)] = (A \cap B) \Delta (A \cap C)[/math]
Justifying the individual steps exercise reader.

>> No.11861968 [View]
File: 220 KB, 1600x1200, __natsuiro_matsuri_hololive_drawn_by_dark_talker__1fe67a4e3cb4c98e33121ffb0f1e5130.jpg [View same] [iqdb] [saucenao] [google]
11861968

>>11861768
>Collette
Thanks for informing me.
>>11861953
If the function [math]F( \epsilon ) = \inf _{x' \in B(x, \epsilon)} f( x')[/math] exists, it's monotonic, and it's bounded above by [math]f(x)[/math], so it has a right limit at [math]0[/math].

>> No.11857927 [View]
File: 220 KB, 1600x1200, __natsuiro_matsuri_hololive_drawn_by_dark_talker__1fe67a4e3cb4c98e33121ffb0f1e5130.jpg [View same] [iqdb] [saucenao] [google]
11857927

>>11857204
Thanks, bro. You'll make it for sure.

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