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>> No.12701615 [View]
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12701615

roll 2 dice
find P( at least 1 die lands on 6 | dice show different #'s )

if first dice is 1 , P = 1/5
if first dice is 2 , P = 1/5
if first dice is 3 , P = 1/5
if first dice is 4 , P = 1/5
if first dice is 5 , P = 1/5
if first dice is 6 , P = 1

thus P = 5( 1/6 * 1/5 ) + 1/6 = 1/3
P( at least 1 die lands on 6 | dice show different #'s ) = 1/3 .

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