/sci/ - Science & Math

>>15823819
Okay, my mistake.
It's not that increasing the amount of gold balls in the pure gold box increases the chance of that box being the one picked, but increasing the amount of silver balls in the other boxes decreases the chances of those ones being picked.
It's still 2/3 from this thing i wrote. My current thought process is:
Box 1 has 1 chance of being an attempt and 1 chance of victory
Box 2 has 2/3 chance of being an attempt and 1/2 chance of victory
Box 3 has 1/3 chance of being an attempt and 0 chance of victory
The chance of attempt AND victory is the multiplication of those factors, while the total chance of victory is the total chance of victory AND attempt divided by total chance of attempt.
So we have (1 + 1/2 * 2/3) / (1 + 2/3 + 1/3)
Which is 2/3
This also works for the original problem.
First box has 1 chance of attempt and 1 chance of victory
Second has 1/2 chance of attempt and 0 chance of victory
So we have 1 / (1 + 1/2). Also 2/3
Correct me if i made a mistake somewhere.
t. Only know high-school statistics