/sci/ - Science & Math

>>6315029
i think that what theyre asking is that if the eigenvalue is not equal to zero.
Correct me if im wrong, but if the minimal polynomial has only one lambda as an eigenvalue, then there is nothing shooting into the null space, and there will be no way to that we can decompose V as we wont be able to write <span class="math">W_1\cap W_2={0}[/spoiler]