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>> No.10207368 [View]
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10207368

>>10207304
No, I didn't get it. So, solutions are all trajectories on the phase plane. They make the DE true. Due to existence uniqueness these lines don't cross other nearby solutions. You're saying that x = 0, x = 1 as functions satisfy the differential equation. This is true because x' = 0 for both. That's my attempt at understanding so far. My calculus knowledge is really rusty, which is why this limit part is throwing me off. I don't understand what the limit of x(t) goes to +-infinity means in this context. I also don't understand how or if the initial condition is relevant at all. Are we supposed to be looking at the trajectory at the initial condition?

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