/sci/ - Science & Math

is this right?

[math]\int \frac{x}{x(x-1)}dx = \int 1 dt = t+c [/math]
[math]\int \frac{-1}{x}+\frac{1}{x-1}dx = \ln(x)+\ln(x-1) =\int 1 dt = t+c [/math]

natural log is undefined at ln(0), so I think I did something wrong as x(0) = 3 couldn't happen then right?