/sci/ - Science & Math

>>11450682
>>11450693
>why does it exist
The second one necessarily exists by definition, that is, it's a multiplication of two numbers which exist.
The first limit exists because it's the exact same as the second one.
>And you HAVE to use that g(0)=0
I used it, tho. That's why [math]\frac{dfg}{dx} (0) = lim_{ \epsilon \rightarrow 0} \frac{fg( \epsilon) - fg(0)}{ \epsilon} = lim_{ \epsilon \rightarrow 0} \frac{fg( \epsilon)}{ \epsilon}[/math], else [math]fg(0)=f(0)g(0)[/math] wouldn't vanish.
Also in the last line, same thing, [math]fg(0)[/math] vanishes.

I used literally everything given, lad.

Grassman was such an absolute unit.