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>> No.11330529 [View]
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11330529

>your ban will expire in 13 days and 17 hours from now
>mfw
>>11330495
>Is it valid to apply newtons law in a rigid body if the forces are not applies in the same spot
Yes. The sum of the forces on a rigid body is equal to the rate of change of linear momentum of the center of mass. [math]
\sum\mathbf{F}=m\mathbf{a}_{cm} [/math]. These forces can be applied to any point on the body.
>Can you apply this law in a point that is not the ICR (Instantaneous centre of rotation):
sum of Torques=angular aceleration*moment of inertia
You have to adjust for possible linear acceleration, but yes. The law becomes [math]
\sum\mathbf{T}=\mathbf{r}_{cm}\times\mathbf{a}_{cm}m+\mathbf{I\alpha} [/math] where the moment of inertia and ang. accel. are both about the center of mass. These torques must all computed from the same reference point, though this reference point doesn't matter.

>> No.11209893 [View]
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11209893

>>11209879
Do you know what "observe" means? Hint: it doesn't mean a human has seen it.

An object is wavelike when it has definite momentum, ambiguous location. An object is particlelike when it has definite location, ambiguous momentum. You can derive from diffraction experiments that
[eqn]2\Delta p\Delta x\geq\hbar[/eqn]
which is called Heisenberg uncertainty. This basically means the product the standard deviation of possible momentum and location is greater than a constant. A wavelike object would have dx dominant, and a particlelike would have dp dominant.

>>11209862
>incel
Are you projecting?

>> No.11209880 [DELETED]  [View]
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11209880

>incel
Maybe you are the one who is projecting?

>> No.11196016 [View]
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11196016

it's time to stop posting

>> No.11191432 [DELETED]  [View]
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11191432

>>11190958
[eqn] Z^{-1}=Z_R^{-1}+Z_L^{-1}+Z_C^{-1}=\frac{1}{R}+\frac{1}{sL}+sC [/eqn]
If you are dealing with a sinusoidal voltage sources (alternating current) then [math] s=j\omega [/math]. Take the reciprocal of [math] Z^{1} [/math] to get equivalent impedance.
[eqn] Z=\frac{sRL}{s^2RLC+sL+R}=\frac{j\omega RL}{R-\omega^2RLC+j\omega L} [/eqn]

>>11190717
I know for a fact that's a weapons range. I drive up that way about once a year to camp and there is pretty much always military aircraft in the air around Ridgecrest.
Fun fact: when you turn off the 395 northbound to the 190 east to head into Death Valley, and before you head through the pass into Panamint Springs, there is a turnoff on the right hand side that leads down a road called Darwin Road. At the end of that road, there is a near-ghost town that has maybe a few dozen weirdos living there. The "town" of Darwin overlooks that weapons range. I don't recommend going there, but it is a definite trip. They all kinda protest the existence of China Lake NAWS.

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