/sci/ - Science & Math

TLDR; How much does your average Joe know about mathematics? How does this vary from America, to Europe, to Asia?

I ask because I want to know how much math I need to know before I can stop feeling so ashamed of my ignorance. Without exaggeration, I grew up surrounded by people who barely even knew grade school arithmetic and geometry, with zero knowledge of Algebra or beyond. Zero. They didn't even know what the Cartesian Plane was. I was also home schooled by these same people and got a GED. Thus, for a long time, I had a severely warped perspective of what constitutes "adequate proficiency in math." Once I started perusing /sci/, I began to realize that I was severely misinformed. I'm not interested in becoming a mathematician, I just want to get up to par and maybe even a little bit above par, relative to ordinary people, but I don't know what ordinary people know.

>>9655983
An enzyme is specific only to amino acid X but gets competitively inhibited by amino acid Y. In the cytoplasm, amino acid Y concentration is 1000-fold greater than amino acid X--not to mention the Km for X is 10 mM while the Ki for Y is 10 uM.

How does the enzyme even function in vivo?

>>9584196
Honestly, I'm surprised he even made it as long as he did.

>>9096710
>You can't
i'm not going to do the full derivation here, but take a look at this section of the wiki article on rotating reference frames

https://en.wikipedia.org/wiki/Rotating_reference_frame#Relation_between_accelerations_in_the_two_frames

Here the equation relates acceleration [math]\vec{a}_i[/math] in an inertial reference frame to the acceleration [math]\vec{a}_r[/math] in a reference frame rotating with constant angular velocity vector [math]\vec{\Omega}[/math]

[math]\vec{a}_r = \vec{a}_i - 2 \vec{\Omega}\times\vec{v}_r - \vec{\Omega} \times(\vec{\Omega}\times\vec{r}) - \frac{d\vec{\Omega}}{dt}\times\vec{r}[/math]

here the [math]\vec{\Omega} \times(\vec{\Omega}\times\vec{r})[/math] term is the fictitious centrifugal acceleration, and the [math]- 2 \vec{\Omega}\times\vec{v}_r[/math] is the coriolis acceleration. The last term [math] - \frac{d\vec{\Omega}}{dt}\times\vec{r}[/math] is called the Euler acceleration, but is zero since we assumed [math]\vec{\Omega}[\math] is constant.

Clearly we can set [math]\vec{a}_i = \vec{0}[\math] for a body with zero net force in an inertial reference frame. Notice how neither of the centrifugal nor coriolis accelerations/forces are forced to zero? That means you can have a fictitious centrifugal force without physical centripetal force.

I will repeat, any connection you form in your head relating centripetal and centrifugal forces is JUST PLAIN WRONG. They are two completely different terms in the force law for a rotating coordinate system.

>>8875375
Yeah, well try to build shit with your feelings and see how far that gets ya