/sci/ - Science & Math

>>6141836
ah, thought so. thanks

>>5583296
YEEAH!!

Really depends on what you want to do!
You can watch MIT and Standford "introduction to programming" youtube video lectures, I consider this the unboring variant.
They start with Java and Python.
I would also reccomment Python, it's a pretty and easy to learn language. The counterargument would be that it has no strict dogma ragarding how to code and I think a little discipline is good.
I personally recomment an easy readable language, like Ziim

http://esolangs.org/wiki/Hello_world_program_in_esoteric_languages

>>5217587
http://en.wikipedia.org/wiki/The_art_of_being_right

>/sci/ is human.
I'm a real human being and a real hero.
What music do you enjoy?
Things like Arcade Fire, Justice and Regina Spektor
What do you study?
Physics
What do you do?
duh

What fascinates you?
Philosophy of science, and people and language.
What's your favorite beer?
Märzen
Liquor?
Vodka
Hobbies?
solving small sci question problems, apparently

If you have an object A, then an inverse B is an object, such that

A·B=1

Since 0·B=0 (and not =1) by the definition of 0, there can't be an inverse of 0 in the algebraic sense presented here.

>Equation
<span class="math">{\Gamma'}^k_{ij} =
\frac{\partial x^p}{\partial y^i}
\frac{\partial x^q}{\partial y^j}
\frac{\partial y^k}{\partial x^r}\Gamma^r_{pq}[/spoiler]
>Sect of Science
philosophy maybe, not sure
>Film
depends on genre
>Documentary
Helvetica
>Sandwich filling
a sweet Hamiltonian

>>3710482
42 minutes late

1)
- the braket of varpsi with psi
or
-the projection of psi onto varpsi
or
-the transition of psi to varpsi
or
-bra varpsi ket psi

notice also that |<b|a>|^2=<a|b><b|a>=<a|P|a>, with P=|b><b|
so thats also the expecation value of the state a the projection on b

2)
- the sandwitch of A between varpsi and psi
or
-the transition of A psi to varpsi

No. However, you should do it. That's the spirit.
The topic is surprisingly lol'zig btw.

I'm doing physics, but here is an idea:

Maby it means that if you consider the field K = Q/(\sqrt{D}) where coefficients m,n \in Q, and D is NOT square free, like p=8, say

D = p1^2 · p2^2 · d, where d is square free

then any element is

A = m · 1 + n · sqrt(D) = m · 1 + n·p1·p2 · sqrt(d)

where you can now, without restrictions, choose m=M, n=N/(p1·p2), such that

A = N·1 + M · sqrt(d),

i.e. the field is K = Q/(\sqrt{d}), with d square free.

Revolutionize Philosophy of science.

I'm being serious here.