/sci/ - Science & Math

>>16014109
copying from an older reply:
Since particle travel through matter the probability of undergoing multiple scattering (due to weak interaction) is greater the beamline vacuum. This limits the resolution of your measurements. For instance,
> assuming a simple beamline (which LHC is NOT)
> Your momentum resolution depends on
> [math]\beta = v/c[/math] which depends the actual speed your particle is going at
< therefore, momentum resolution before adding the detector noise etc:

[eqn]\frac{\sigma_p^{\mathrm{ms}}}{p}=\frac{\Delta p_x^{\mathrm{ms}}}{\Delta p_x}=\frac{0.0136 \cdot \cos \lambda}{0.3 \beta B L} \cdot \sqrt{\frac{L_{\mathrm{T}}}{X_0}}[/eqn]

Not only this but energy loss in matter can also be described as:
> energy loss means deposited energy in your detectoe (which makes up your measurement)
> energy loss also means ionization factor!

[eqn]-\frac{d E}{d x}=\frac{4 \pi n z^2 e^4}{m_e v^2} \int_{b_{\min }}^{b_{\max }} \frac{d b}{b}=\frac{4 \pi n z^2 e^4}{m_e v^2} \ln \frac{b_{\max }}{b_{\min }}[/eqn]

Higher energies penetrate deeper into matter without losing energy. Along the Radiation length [math]\Chi_0[/math], the Bragg peaks (max energy deposit) also depends on speed of the particle!
> see picrel for the penetration depth vs energy deposited vs energy of particle

[eqn]E_{\text {Compton }}=E_T(\max )=E\left(1-\frac{1}{1+\frac{2 E}{m_{\mathrm{e}} v^2}}\right)[/eqn]

so if we have bigger boom it should get better.

>>16014139
I agree with this anon too, we should more or less look for anomalous materials. Not talking about qubits necessarily but perhaps also metamaterials and >>THz ranges

>>16020492
as an engineer I have to agree they only know how to use python nowadays. I've met with exceptional cases too, but they also are fixated on abstracted layers of bullshit like the higgs chain.

>>16020793
>Will people freak out again like last time?
i hope so will be very funny

>>16013666
Apparently since no one knows shit about particle physics, allow me to explain. I work at a CERN adjacent institute.

Since particle travel through matter the probability of undergoing multiple scattering (due to weak interaction) is greater the beamline vacuum. This limits the resulotion of your measurements. For instance,
> assuming a simple beamline (which LHC is NOT)
> Your momentum resulution depends on
> [math]\beta = v/c[/math] which depends the actual speed your particle is going at
< therefore, momentum resulution before adding the detector noise etc:

[eqn]\frac{\sigma_p^{\mathrm{ms}}}{p}=\frac{\Delta p_x^{\mathrm{ms}}}{\Delta p_x}=\frac{0.0136 \cdot \cos \lambda}{0.3 \beta B L} \cdot \sqrt{\frac{L_{\mathrm{T}}}{X_0}}[/eqn]

Not only this but energy loss in matter can also be described as:
> energy loss means deposited energy in your detectoe (which makes up your measurement)
> energy loss also means ionisation factor!

[eqn]-\frac{d E}{d x}=\frac{4 \pi n z^2 e^4}{m_e v^2} \int_{b_{\min }}^{b_{\max }} \frac{d b}{b}=\frac{4 \pi n z^2 e^4}{m_e v^2} \ln \frac{b_{\max }}{b_{\min }}[/eqn]

Higer energies penetrate deeper into matter without losing energy. Along the Radiation length [math]\Chi_0[/math], the Bragg peaks (max energy deposit) also depends on speed of the particle!
> see picrel for the penetration depth vs energy deposited vs energy of particle

[eqn]E_{\text {Compton }}=E_T(\max )=E\left(1-\frac{1}{1+\frac{2 E}{m_{\mathrm{e}} v^2}}\right)[/eqn]

so the energy makes all the measurements better! Not giving my taxmoney to that shit though. I need me some funding for my project. I need EU gib funds. Anyhow correct me if I'm wrong particlechads or physicsmaxxers.