/sci/ - Science & Math

>>11753314
If you have a right triangle with hypotenuse [math]c[/math], then the other sides would be [math]a = c\cdot\cos (\alpha), b= c\cdot\sin (\alpha)[/math], and so the area would be [math] \frac{ab}{2} = \frac{c^2}{2}\cos (\alpha)\sin (\alpha) = \frac{c^2}{4} \sin(2\alpha)[/math]. In this way you could write the area as a function of the hypotenuse and an angle, but you would still have two pieces of information.