/sci/ - Science & Math

Anonymous Thu Dec 8 19:56:14 2022 No.15039958 [View]
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>>15039943
>Is this fine?
Yes.
>i don't see an obvious way to come up with one
Assume [math]F(A) = F(B)[/math] where [math]A \neq B[/math]. Then [math]F(id_{A}) = id_{F(A)} = id_{F(B)} = F(id_{B})[/math], which contradicts [math]F[/math]'s injectivity on morphisms.
The faithful part is trivial.

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/sci/ - Science & Math

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