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>> No.16207620 [View]
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16207620

>>16131221
yee haw

>> No.15927950 [View]
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15927950

>>15925528
it makes sense to me as the pythagorean formula applied to a right triangle with 1 real leg longer than the real hypotenuse, forcing the other leg to go imaginary. I was able to get Euler's formula by farting around with the single-variable function and parametric equation ways of expressing a circle and out-of-bounds hyperbola or vice-versa, getting some sorta expression with arcsinh(arcsin()), then differentiating and immediately integrating. That last part was a simple enough way to get around sin and arcsin not having closed forms, but I haven't seen it done before and I'm not sure if it's correct or if it just agrees with the answer I was looking for. I wrote it all down but I'm not at home, might have time tomorrow to rewrite it and post. All in all I don't find that 'trick' much more enlightening than the usual proof through infinite series.

>> No.15808741 [View]
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15808741

I'm pretty sure the root of the connection is when you force the Pythagorean identity on improper right triangles, on right triangles where x > r, so that y has to be complex in order for the x^2 + y^2 = r^2 to hold. I'm looking for a clean way to show it with geometry/algebra, not sure if it's possible

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