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/sci/ - Science & Math

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>> No.3647409 [View]
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[ERROR]

>>3647377

>> No.3086770 [View]
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3086770

>>3086762
FUCKYES.JPG

>> No.2724412 [View]
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2724412

>> No.2702930 [View]
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2702930

Dammit OP now I'm pumped.

>> No.2380059 [View]
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2380059

>>2380032
Oh man, thank you very much for that, that is very helpful!

Any other suggestions or areas of focus?

>> No.2351039 [View]
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2351039

If you wanted to work it all out you'd use seperation of variables.

dy/dt + 2y = 0
dy/dt = -2y
multiply the dt over to the right, and divide by the y
1/y dy = -2 dt
Now integrate both sides
ln(y) = -2t + c
Raise each side to the power e
y = e^(-2t + c)
y = e^(-2t)*e^c
e^c is just another constant, so you now you have
y = ce^(-2t)
Now apply initial conditions.
3 = ce^0
c = 3
So your final answer is
y = 3e^(-2t)

>> No.2165440 [View]
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2165440

>>2165429

Do it if you're a man. Which you are.

Be alpha as fuck, do the classes! (do the calculus)

>> No.2151738 [View]
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2151738

>Agnostic: There is a chance that both sides could be right but considering we can't prove or disprove either I'd rather deal with other shit instead of argue.

I love grey areas.

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