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>> No.15082112 [View]
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15082112

>>15082101
>As for the difference thing I don't get why I should do that? Why should it be constant? I'm not talking about a specific case here.
[math]\Delta ^{n + 1} p(x) = 0[/math] if [math]p(x)[/math] is a polynomial of degree [math]n[/math]. If you prove the converse, your desired result immediately follows since [math]\Delta \sum_{t = 1}^x F(t) = F(x + 1)[/math], a polynomial.
>I'm not talking about a specific case here.
I have absolutely no idea what do you mean by that.

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