/sci/ - Science & Math

That is to say, 1(n)+2(n-1)+3(n-2)+...+(n-2)3+(n-1)2+(1)n
Can this be simplified, like 1+2+...+n=n(n+1)/2 ? If you find an answer, I'd love to know how you got it. I'll post some things I've noticed about this in case it helps.