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>> No.11648878 [View]
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11648878

>>11648861
>you'll see it's reflected into the opposite quadrant of your point.
Can you elaborate a bit on this point? I plotted 2pi/3 onto the desmos polar coordinate graph and it's in Quadrant 1 which fits the domain of 0->2pi doesn't it? Sorry, I'm really bad at this.
>The rule you'll have to follow is that if your point is below the x-axis you'll have to add pi to the angle to get it right.
This makes a lot of sense, I changed it to 4pi/3 and got it right, I'll remember this for the future, thank you!

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