/sci/ - Science & Math

>>12211385
Let [math]Q[/math] be the field of fractions of an integral domain [math]R[/math]. Then [math]|R| \le |Q| \le |R| \times |R|[/math], so it will be the same in the case [math]R[/math] is infinite. If [math]R[/math] is finite, then it is a field already, and so it is its own field of fractions. The answer is yes.