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/sci/ - Science & Math

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>> No.5735945 [DELETED]  [View]
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5735945

Lets say someone operates a business that does your particular field of science or engineering.

HOWEVER. It is 20 years from now and the past few generations have grown up. This business has been themed after an "evil villain" organization. Bond villains, Venture Brothers villains, have what you want.

It is a themed business. You are being offered your usual wage, with acceptable benefits. However you MUST wear a uniform themed after the organization.

The owner of the business insists that this is all legal work and he is only a fan of the villain theme.

Do you work for him? Would you run such a business yourself?

>> No.5705804 [View]
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5705804

I'm 25 and going back to college to be an Engineer (in what specifically I am unsure, primarily looking at general Mechanical Engineering, with a high interest in robotics.)

However, people keep telling me I should go Navy. Nuke Tech especially. I know that isn't for me...but are there other military engineering jobs I could get that would spring board me forward?

/k/ was of no help.

>> No.5037460 [View]
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5037460

>>5037449
Notice how we are always talked about on the internet guys. I never hear anything about Europe. Just 'merica. Take notice. You'll see that there is general butthurt around the internet and, honestly, the world. Just makes me laugh.

>> No.5025291 [View]
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5025291

this dog is cute. I'm posting.

also, what's with the autism?

>> No.4849614 [View]
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4849614

I hope the following method may give good results.

The out put current Is in the transformer secondary is given by ..

Vs Is = Vp Ip x 0.95
Is = 22 x 100 x 0.95 / 240 = 8.708 A

The power loss during transmission without step up and with step up are ...
P1 = Ip^2 R
P2 = Is^2 R
R is the resistance of the copper wire of length 2l = L = 30x10^3 m
Specific resistance of copper = pi d^2 R /4 L , where d = 4x10-3 m
R =
So if I know the specific resistance I get the value of R
(P1 - P2) gives the difference in power loss in watts.
This can be converted into Kwh and hence the saving
___________________
Sp.resistance of copper = 1.7x120^-4 ohm-m
R = 4.058x10^5 ohms
P1 = 405.8 x10^7 watts
P2 = 3.078x10^7 watts
P1 - P2 = 402.7 x10^7 watts
Difference in Power consumed per day
= (P1 - P2)x10^-3 x3600 x 24 Kw
Difference in the no. of units of power consumed is
(P1 - P2)x10^-3 x 24 / 3600 Kwh = 9.665 x10^7 Kwh
This multiplied by the currency gives the money saved

>> No.4716070 [View]
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4716070

>>4716059
meh atleast I'll know a lil thing of everything I like. Plus I'll be making more money than you as a doctor (specifically, a neurosurgeon)

>> No.4701890 [View]
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4701890

Delving into history always makes my brain feel revitalized. It's something I can't explain, but I definitely feel quicker after I've researched an amazing era.

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