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>> No.11115648 [View]
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11115648

>>11113787
I dunno, do I look like I browse /g/?
R is the only language I know.
>>11113994
>is this analysis
Yes.
>>11114545
That wasn't an answer, that was a comment.
An answer would've been "Studying anywhere is easy" or something along those lines.
>>11114684
[math]\sqrt{2(x^2+y^2})+2= \sqrt{2}\sqrt{(x^2+y^2} + 2[/math], and the inequality is equivalent to [math](2- \sqrt{2}) \sqrt{x^2+y^2} > 2[/math].
Since [math]2- \sqrt{2} > \frac{1}{2}[/math], we have that [math] (2 - \sqrt{2}) \sqrt {x^2 + y^2} \geq \frac{1}{2} * \sqrt{32} \geq 2[/math].
I give the inequality a weak 2/10. Are you sure that you have x, y>4? The inequality should be strict.
I've checked it at least five times now, but I still get the impression it's wrong.

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