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>> No.12438015 [View]
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12438015

We're all getting physically older all the time.
But what's a way not to become old mentally? And I don't mean memory and thinking capcity - I mean becoming a boomer, someone nobody really wants to be around. Someone who's only friends with their wives. Some old mathematician who writes blog posts like John Baez. Somebody who's life is over.
How to avoid?

>> No.11054873 [View]
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11054873

>>11054836
sorry

>>11054846
>to grasp without much effort

>> No.10967182 [DELETED]  [View]
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10967182

>>10967132
You'll find C represented in any C-vector space, so that's moot.
Also, the matrices he wrote down aren't in su(2). If the unity matrix were in it, SU(2) wouldn't even be compact (let alone unitary).

>> No.9646106 [View]
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9646106

>take a DNA test on 23andnormie
>it finds a first cousin I've never heard about
>ask my parents about it
>they get pissed because it was a secret love child from my uncle who not even his kids or anyone knows about

Are DNA tests too powerful?

>> No.8908977 [View]
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8908977

>>8908910
If I had to guess, I think he posted Newtons method to find zeroes of a function, and which has some continuity requirements.
https://en.wikipedia.org/wiki/Newton%27s_method
Meaning the sequence is the point in the recursion and the starting point is arbitrary

>>8908868
Here some more

[math] \sin(z) = z\prod_{n=1}^\infty \left(1-\left(\frac{z}{n\,\pi}\right)^2\right) [/math]

it's awesome, I agree

[math] \dfrac{1}{\sin(z)} = \dfrac{1}{z} + 2z\sum_{n=1}^\infty (-1)^n \dfrac{1}{z^2 - (n\,\pi)^2} [/math]



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