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/sci/ - Science & Math

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>> No.11879648 [View]
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11879648

>>11879615

>> No.9196619 [View]
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9196619

How does sci write fraktur? should I even bother trying?

>> No.8424461 [View]
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8424461

nice pasta there luigi

>> No.8324792 [View]
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8324792

>came to sci to talk about CP-violation

I see no problem here

>> No.7207709 [View]
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7207709

>>7207461
my fav

>> No.7046447 [View]
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7046447

Sup /sci/?

I'm scheduled to give a short 12 minute presentation in a couple of days. The subject is an article on tandem catalysis published in 2014.

My question to you is, how do you structure your scientific presentations?

My plan was to have to following outline:

Introduction (Why did they do it, what was already known?)
Methods (How did they do it?)
Results (What did they find out?)
Discussion and Critique (How valuable is this research? What could be improved in the future?)

>> No.6444560 [View]
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6444560

>> No.6324629 [DELETED]  [View]
File: 299 KB, 479x359, tmp_13881715683851423542777.png [View same] [iqdb] [saucenao] [google]
6324629

If I do an undergraduate degree in Mathematics can I go on and do a graduate degree in Physics? They're not that far apart I hear.

>> No.6190965 [View]
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6190965

>> No.6134209 [View]
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6134209

I want a program that asks for a function as input and gives f(2) and f(3). I tried this:
f=lambda x: input('f=')
print f(2),f(3)
Of course it doesn't work because every time it runs it asks for input. So it asks once for 2 and another for 3.
How can I define the function only once?

>> No.6104763 [View]
File: 299 KB, 479x359, 1371690542523.png [View same] [iqdb] [saucenao] [google]
6104763

Hey /sci/,

Is this a good proof that 3^n >= n^3, for n element of N? It looks sorta ugly:

(Induction) Base case, n=1: 3^1 >= 1^3

Inductive step:
3^n >= n^3
3^(n+1) >= n^3 * 3

Now we prove n^3 * 3 >= (n+1)^3

Take cuberoot:
n * 3^(1/3) >= n + 1
(3^(1/3) - 1)*n >= 1,

which is true for n>=3 and since n * 3^(1/3) >= n + 1 is true for n=2 and in the base case we have proven for n=1, it follows its true for all n.

I've checked everything and I looks like I didn't make any mistake. It just look so damn ugly.

>> No.6081796 [View]
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6081796

>>6081790

I know, losing control of your muscles isn't an excuse to pull silly faces

>> No.6014077 [View]
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6014077

>> No.5970823 [View]
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5970823

>> No.5950918 [View]
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>> No.5937659 [View]
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5937659

>> No.5901390 [View]
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5901390

>> No.5871102 [View]
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5871102

>> No.5856765 [DELETED]  [View]
File: 299 KB, 479x359, 1371690542523.png [View same] [iqdb] [saucenao] [google]
5856765

Can someone explain component wise vector multiplication to me? I just can't find a good source on the Internet.

How does [0,1] x [0.2575, 0.7425] equal [0,1] (where x is the component-wise multiplication)?

Makes no sense to me, unless [a,b] x [c,d] = [a*c + a*d, b*c + b*d]?

>> No.5846125 [View]
File: 299 KB, 479x359, stephen hawking.png [View same] [iqdb] [saucenao] [google]
5846125

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