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>> No.15235398 [View]
File: 3.74 MB, 1932x2132, __furude_rika_and_houjou_satoko_higurashi_no_naku_koro_ni_drawn_by_fuyu_wldnrowldnro__2f5d1ce1d4f326789eab209c92a4f419.png [View same] [iqdb] [saucenao] [google]
15235398

>>15234941
the lines x = 0 and x = 1 intersect at the same point on the line at infinity because they have the same slope. they both go over the north pole.

>> No.15086243 [View]
File: 3.74 MB, 1932x2132, __furude_rika_and_houjou_satoko_higurashi_no_naku_koro_ni_drawn_by_fuyu_wldnrowldnro__2f5d1ce1d4f326789eab209c92a4f419.png [View same] [iqdb] [saucenao] [google]
15086243

>>15074690
what is "wafer resolution"?

>> No.15053709 [View]
File: 3.74 MB, 1932x2132, __furude_rika_and_houjou_satoko_higurashi_no_naku_koro_ni_drawn_by_fuyu_wldnrowldnro__2f5d1ce1d4f326789eab209c92a4f419.png [View same] [iqdb] [saucenao] [google]
15053709

>>15053685
fyi this has nothing to do with the original question. let me try to explain it better:
we are trying to prove that [math]n! \geq 4^n[/math] for [math]n \geq 9[/math]. we know just by calculating that [math]9! \geq 4^9 [/math], so we only need to show that [math]n! \geq 4^n[/math] implies [math](n+1)! \geq 4^{(n+1)}[/math] to finish the proof, and we still get to assume that [math]n \geq 9[/math]. we will begin by assuming that [math]n! \geq 4^n[/math] is true, and we'll try to algebraically manipulate it into [math](n+1)! \geq 4^{(n+1)}[/math]. we can do this by multiplying the left side by [math]n+1[/math] and the right side by [math]4[/math]. are we allowed to do this? well, we know that [math]n+1[/math] is definitely bigger than [math]4[/math], since [math]n \geq 9[/math], so doing this will preserve the inequality. we thus prove the inductive step and conclude the proof.
>>15053404
well best of luck to you fren. try to take a computer architecture course if you can.

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