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>> No.9179469 [View]
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9179469

Having a bit of problem with electromagnetics.
I'm being asked the question in pic related.

Since I know that the E field can be given by
[eqn]\mathbf{E}={\frac{1}{4\pi\varepsilon}}\int_{V}\frac{\rho_v}{R^2}\:dV[/eqn]

And since [math]\mathbf{D}=\varepsilon\mathbf{E}[/math]

Then is this true?

[eqn]\mathbf{D}={\frac{1}{4\pi}}\int_{V}\frac{\rho_v}{R^2}\:dV[/eqn]

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