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>> No.11225506 [View]
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11225506

>>11225502
Curvature, slope and deflection of a beam.

>> No.11197879 [View]
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11197879

>>11197809
Suppose
[eqn] f_k(x)=k\ \ \text{when}\ -\frac{1}{k}\leq x\leq\frac{1}{k}\ ;\ \ f_k(x)=0\ \ \text{otherwise} [/eqn]
and suppose
[eqn] \delta(x)=\lim_{k\to\infty}f_k(x) [/eqn]
therefore
[eqn] \int_{-\infty}^{\infty}\exp(-sx)\cdot\delta(x)\text{ d}x=\mathcal{L}\big(\delta(x)\big)=1 [/eqn]
and
[eqn] u(x)=\int_{-\infty}^x\delta(t)\text{ d}t [/eqn]

>> No.11062918 [View]
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11062918

Gonna ask again, since tictac niggers can't seem to answer the question.
What exactly am I trying to refute?

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