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>> No.9323583 [View]
File: 3 KB, 413x237, Riemann.gif [View same] [iqdb] [saucenao] [google]
9323583

Post beautiful equations.

>> No.8933413 [View]
File: 3 KB, 413x237, IMG_1177.gif [View same] [iqdb] [saucenao] [google]
8933413

>>8933284
So bare with me a little but let's assume that the statement below is true.

3/3 = 1 = .9999...

If so, do you think that this can help account for why

1+2+3+4+6+.... = -1/12
(.999...)+(.999...+.999...)+... = 1/12

>> No.8933204 [View]
File: 3 KB, 413x237, IMG_1177.gif [View same] [iqdb] [saucenao] [google]
8933204

>>8930892

>> No.8884466 [View]
File: 3 KB, 413x237, Riemann.gif [View same] [iqdb] [saucenao] [google]
8884466

Post beautiful equations.

>> No.8799319 [View]
File: 3 KB, 413x237, Riemann.gif [View same] [iqdb] [saucenao] [google]
8799319

>>8793027

>> No.8734255 [View]
File: 3 KB, 413x237, q0XjQ.gif [View same] [iqdb] [saucenao] [google]
8734255

If S=-1, explain how it can equal -1/12.

>> No.8734214 [DELETED]  [View]
File: 3 KB, 413x237, q0XjQ.gif [View same] [iqdb] [saucenao] [google]
8734214

S=1

Discuss.

>> No.8564463 [View]
File: 3 KB, 413x237, ramen noodles function.gif [View same] [iqdb] [saucenao] [google]
8564463

zeta(-13) = zeta(-1) = -1/12

can we prove that s = -13 and -1 are the only rational whole numbers in the zeta function that
= -1/12?

>> No.7691564 [View]
File: 3 KB, 413x237, Pierre Linus Jobs.gif [View same] [iqdb] [saucenao] [google]
7691564

>I have discovered a truly remarkable proof which this post is too small to contain.

>> No.6910171 [View]
File: 3 KB, 413x237, R Zeta Function.gif [View same] [iqdb] [saucenao] [google]
6910171

How does it feel knowing that we just gave an arbitrary number to a sum that should equal infinity?

I've never seen the amount of stupidity from Mathematicians, an equation that gives a certain sequence is just accepted and said, well you know what? It works for all numbers but 1. Let's use it, it must be right!

Prove to me otherwise that 1+2+3... =/= Infinity, without the Riemann Zeta Function

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