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/sci/ - Science & Math

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>> No.8592071 [View]
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8592071

I am to write an assignment, which needs to be a fusion of maths and physics. I was thinking about complex numbers in physics, but after reading up on complex numbers, what can complex numbers achieve in physics?

>> No.7271687 [View]
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7271687

>>7271112
sqrt(-1) = i
BUT what does sqrt(i) equal????

Atheists: 0
Btheists: i

>> No.6241639 [View]
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6241639

Can someone explain to me how (2/i) ln(i) = pi?

>> No.3572215 [View]
File: 19 KB, 400x400, i and pi.gif [View same] [iqdb] [saucenao] [google]
3572215

>>3572207
150 is the cut off. Beyond that you need a survelience state or religiousity.

>> No.3160345 [View]
File: 19 KB, 400x400, i and pi.gif [View same] [iqdb] [saucenao] [google]
3160345

>>3160337
>CHING CHONG POTATO

>> No.3145099 [View]
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3145099

>>3145053
I'm real concerned this irrational thread is becoming imaginary

>> No.2412694 [View]
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2412694

hey /sci/ I hope this isn't construed as a "homework help" thread . . .

I'm having trouble grasping the concept of imaginary numbers (i)

for whatever reason it just confuses me to no end. Our teacher has taught us how to solve problems with (i) but I don't understand the application or the "why"

I hope that's descriptive enough to get some answers

>> No.2172371 [View]
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2172371

I pose a question and a challenge to you.

There are a set of functions which have a certain periodicity. Let me define a variable n which is contained on the set of integers.

The function which has a periodicity of 1 is 1^n. Basically after 1 alteration of n you get back to the same answer.

The function which has a periodcity of 2 is (-1)^n. After altering n twice you get back to the same answer (i.e. (-1)^1=-1, (-1)^2=1, (-1)^3=1).

The function which a periodicity of 4 is (i)^n (i being the complex number). After altering n 4 times you get back to the same answer (i.e (i)^1=i, (i)^2=-1, (i)^3=-i, (i)^4=1, (i)^5=1)

What is the function which has a periodicity of 6?

>> No.1788065 [View]
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1788065

can you help me solve this?

z=1/(1-bi)+1/(1+i) where b is a real number.

decide the values of b that makes z a real number

>> No.1336260 [View]
File: 19 KB, 400x400, numbers_2D5DB59D-0675-C999-64717CDD29BA84D3.gif [View same] [iqdb] [saucenao] [google]
1336260

Y'all know imaginary numbers are rational right? There are infinite rational solutions.

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