[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

Search:


View post   

>> No.11011189 [View]
File: 341 KB, 2776x583, F790AEE9-2EB2-4EFB-BEBC-5B9C40D39893.jpg [View same] [iqdb] [saucenao] [google]
11011189

Anyone help me with this problem? I tried a few answers but got it wrong and I only have 1 more chance.

Probability = number of wanted outcomes/number of possible outcomes

So from seat 2 we can possibly go to (4,5,6). i think to find m/n, I want to multiply the probability of 4, times probability of 5 times probability of 6. but this is where I am confused.

At p4, i have a 1/3 chance of landing on 1 (1,2,6), at p5 i have a 1/3 chance of landing on 1 (1,2,3) but at p6, our only possibilities are (3,4,5) so wouldn’t that give me 0/3 chance of landing on 1?
Am i looking at this incorrectly?

Navigation
View posts[+24][+48][+96]