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# /sci/ - Science & Math

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 >> Anonymous Sun Sep 20 11:59:46 2020 No.12142459 [View] File: 27 KB, 700x467, Smiling British Pepe.png [View same] [iqdb] [saucenao] [google] [report] >>12142410>Keep getting/seeing 4r/3piThat's the centroid of a solid/filled semicircle. You need to use the centroid of a semicircular arc to find the surface area of a sphere.
 >> Anonymous Wed Sep 16 00:51:04 2020 No.12126539 [View] File: 27 KB, 700x467, Smiling British Pepe.png [View same] [iqdb] [saucenao] [google] [report] >>12126424>BEMDASNah, we call it BODMAS (O stands for order) or BIDMAS (I stands for indices/index).
 >> Anonymous Mon Sep 7 14:01:01 2020 No.12095309 [View] File: 27 KB, 700x467, smiling British Pepe.png [View same] [iqdb] [saucenao] [google] [report] >>12095000You need to figure out how many rolls yield a given value $k$ and divide this by the total number of possible rolls ($400$ in this case, which I hope is obvious).When trying to calculate the number of rolls which output a given value, start small. Clearly, $(1,1)$ is the only roll which will yield $1$. Then $(1,2)$, $(2,1)$ and $(2,2)$ will output $2$. If you imagine the problem visually (as a $20 × 20$ grid), a pattern is already forming. $k=1$ gave a $1 × 1$ square, then $k=2$ extended this to a $2 × 2$ square. As we increase $k$ we just keep adding L-shapes to extend this square. For any value of $k$, this L-shape consists of $2k - 1$ outcomes (I'll let you verify this yourself). This gives us a probability distribution defined by [eqn]P(Y = k) = \frac{2k - 1}{400}[/eqn]
 >> Anonymous Sat Sep 5 13:32:24 2020 No.12088456 [View] File: 27 KB, 700x467, 1583878742628.png [View same] [iqdb] [saucenao] [google] [report] >>12088145Yes. You can group the $1 bills into piles of 20 and there would be exactly as many* piles of$1 bills as individual \$20 bills. This quantity is denoted $\aleph _0$*formally, this means you can create a bijection between them https://en.wikipedia.org/wiki/Bijection
 >> Anonymous Sun Aug 30 12:05:58 2020 No.12066367 [View] File: 27 KB, 700x467, 1583878742628.png [View same] [iqdb] [saucenao] [google] [report] >>12065721>>12065721Maybe check out the Khan Academy: www.khanacademy.org/mathThere's quite a lot of algebra on there and the Precalculus section has complex numbers
 >> Anonymous Mon Aug 24 00:21:44 2020 No.12042076 [View] File: 27 KB, 700x467, 1583878742628.png [View same] [iqdb] [saucenao] [google] [report] >>12041890Write the playback speed as a fraction (e.g. $1.5 = \frac{3}{2}$). Flip over this fraction and multiply it by the video length. The result is the time it will take to watch the video at the given speed.
 >> Anonymous Wed Aug 12 11:50:38 2020 No.12001195 [View] File: 27 KB, 700x467, 1583878742628.png [View same] [iqdb] [saucenao] [google] [report] >>12001105>>12001147https://www.bbc.co.uk/bitesize/guides/zg6vcj6/revision/6Just gotta keep track of the minus signs bud
 >> Anonymous Thu May 7 01:26:19 2020 No.11645489 [View] File: 27 KB, 700x467, 1583878742628.png [View same] [iqdb] [saucenao] [google] [report] >>11645120Yep

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