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/sci/ - Science & Math

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>> No.9668508 [View]

mathematics PhD student here
if anyone has any questions on math grad school let me know and i'll reply whenever i decide to check the thread again

t. mathfag

>> No.9132198 [View]
File: 50 KB, 410x266, Econometrics_in_Practice.jpg [View same] [iqdb] [saucenao] [google]
9132198

Planning to start with bachelor Econometrics this year (similar to econ + math study combined, heavily math based). Do you guys have any advice for me to succeed in this study?

>> No.8472003 [View]
File: 168 KB, 727x682, 827.png [View same] [iqdb] [saucenao] [google]
8472003

Will a PhD in organic chemistry make me able to synthesize LSD or DMT?

>> No.8338930 [View]

no

>> No.8309669 [View]

/hm/ is where I live now, someone send help.

>> No.8309664 [View]

Reason why I believe I should be doing integration by parts is because the entire assignment was integration by parts. I will be using /hm/

/Thread

>> No.8309653 [View]
File: 10 KB, 196x82, Help.jpg [View same] [iqdb] [saucenao] [google]
8309653

Unsure how to apply integration by parts for this integral. Help me out?

>> No.5961004 [View]

>>5960999

The entire point of inventing numbers that don't work is so that you can solve those kinds of problems

>> No.5960998 [View]

The entire point of imaginary or complex numbers is to solve certain classes of algebraic problems.

There are two ways to represent a polynomial. There's the sum of products: a + bx + cx2 + dx3.. There's the product of sums: k(x+a)(x+b)(x+c)...

Now, every product of sums can be expanded by multiplying out the terms. But, with real numbers, not every sum of products can get factored into a product of sums.

Let's make one such example. x2 + 1. Let's factor it out with a dummy variable, j. So it's (x+j)(x-j) = x2 + 1, which means that j2 = -1.

Anyhow, this idea is called algebraic closure. It means that regardless of what polynomial you have, if numbers are complex, you can factor that shit.

>> No.5562401 [View]

>>5562357
ah i remember this
see that when you get those two "things"(X + 3) the same the 3xsquared and the -5 are then put in a seperate parentheses, thus if you would carry out the process of FOIL, you would get your starting equation. Youre basically simplifying the original equation.

>> No.5438018 [View]

Almost everybody here felt (feels) the same way at some point (but they don't want to admit it)

>> No.5360938 [View]

<span class="math">
\frac{\frac{1}{3}(\frac{1}{3}+1)+\frac{1}{5}(\frac{1}{5}+1)-\frac{1}{15}(\frac{1}{15}+1)}{2}1000^{2}
[/spoiler]

>> No.5193640 [View]
File: 75 KB, 500x376, 1339007434387.jpg [View same] [iqdb] [saucenao] [google]
5193640

How would one go about creating a modulus function in a programming language where you can only use addition, subtraction, multiplication, and division?

I can think of one way (I'll be writing this in C-like code)
to calculate 8436 % 10:

int a = 8436; // declare integer value a
int b = a / 10; // b = 843 (integer division)
b = b * 10; // b = 8430
int c = a - b; // c = 8436 % 10 = 6

Are there any more efficient ways of programming something like this?

>> No.4923767 [View]

>>4923757
You're missing {{a,c},{b}}

>> No.4923769 [View]

>>4923765
A TROLL thread on probability. There's a difference between trolls and threads with merit.

>> No.4923758 [View]

>>4923754
>>4923742
>>4923743
Yes, I'm sure; it's stale troll copypasta. Also, very funny on the samefag, but you're trying too hard.

>> No.4923740 [View]

>>4923719
>>4923726
>>4923730
>>4923735
>>4923731
>>4923734
c'mon, guys, this is stale /sci/ troll copypasta.

>> No.4923716 [View]

staaaaaaaale

>> No.4819892 [View]

>>4819533
Thanks for the advice.

>> No.4819501 [View]

>>4819399
I study at ESFM, and i was thinking of studying at cinvestav, but i'm not sure if i should continue at ESFM on my master's degree or if i should go to cinvestav, what do you i should do?

captcha:
convocación itestns

>> No.4819474 [View]

B

>> No.4760301 [View]

Rook left two, from initial position.

>> No.4721122 [View]

>>4721050
The answer is no, that's not known. My post was entirely true.

Dumbass.

>> No.4721107 [View]

>>4721050
Oh, is it true for connected closed aspherical manifolds?

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